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1.  You have a weighing machine, and you have 27 balls in which 26 balls are of same weight and 1 ball is of different weight. How many times/steps needed to identify the 1 ball which is different from other ball?

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u r correct...I overlooked it....nitin I believe your first solution was correct..cheers :)

hahahaha

Thanx this all is for my friends

Maximum it will take 4 steps...

27= 13+13+1(weigh 13 13 group. if equal the remaining ball is different, else next step)

13=6 +6+1 (weigh 6 6 group. if equal the remaining ball is different, else next step)

6=2+2+2(weigh each group counter to the two balls{<1+1> <left in each step above>} )

2=1+1(weigh each ball counter with any of the upper left balls ...we will find  the answer)

Thank u..

Tim

is it ok now...?

Thanks for correcting me.

No yaar again u do that? ok if deffective ball is in first 13 ball then??? you doubles your steps i.e. 8...may i right tim?
Nitin is right.