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Sorry mr. Suseentheran
we have to find out by weight not by formula
> implying "step" is a formation of logical grouped interactions.
assuming a "step" is one use of the weighing machine you would need 3-26 steps (or if you know that the defect ball is lighter/heavier only 2-25).
as i stated earlier it is.
But the method mentioned by Vineet would take the 3-26 or 2-25 steps.
take 13-13(If weight is balanced the rest is the one which we are searching) else take the 13 which weighs more,
now make it as 6-6(If weight is balanced the rest is the one which we are searching) else take the 6 which weighs more,
now make it as 3-3. Obviously there will be diff in one side. so take that THREE
now make it as 1-1, If weight is balanced the rest is the one which we are searching.
I dont think so...whether heavier or lighter it will work.
consider the weight of 6 balls as 2,2,2,2,2,3 or 1...now it will work with what I said.
yeah but you won't know which group of 13 balls you have to proceed with when one group is lighter, as you don't know if the defect ball is in the lighter group (->the defect means light) or other way around.
given these 2 groups of a different weight and the knowledge of one defect doesn't let you decide which group conains the defect ball.
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